Integrand size = 21, antiderivative size = 106 \[ \int \frac {(d+i c d x) (a+b \arctan (c x))}{x^4} \, dx=-\frac {b c d}{6 x^2}-\frac {i b c^2 d}{2 x}-\frac {d (a+b \arctan (c x))}{3 x^3}-\frac {i c d (a+b \arctan (c x))}{2 x^2}-\frac {1}{3} b c^3 d \log (x)-\frac {1}{12} b c^3 d \log (i-c x)+\frac {5}{12} b c^3 d \log (i+c x) \]
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Time = 0.07 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {45, 4992, 12, 815} \[ \int \frac {(d+i c d x) (a+b \arctan (c x))}{x^4} \, dx=-\frac {d (a+b \arctan (c x))}{3 x^3}-\frac {i c d (a+b \arctan (c x))}{2 x^2}-\frac {1}{3} b c^3 d \log (x)-\frac {1}{12} b c^3 d \log (-c x+i)+\frac {5}{12} b c^3 d \log (c x+i)-\frac {i b c^2 d}{2 x}-\frac {b c d}{6 x^2} \]
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Rule 12
Rule 45
Rule 815
Rule 4992
Rubi steps \begin{align*} \text {integral}& = -\frac {d (a+b \arctan (c x))}{3 x^3}-\frac {i c d (a+b \arctan (c x))}{2 x^2}-(b c) \int \frac {d (-2-3 i c x)}{6 x^3 \left (1+c^2 x^2\right )} \, dx \\ & = -\frac {d (a+b \arctan (c x))}{3 x^3}-\frac {i c d (a+b \arctan (c x))}{2 x^2}-\frac {1}{6} (b c d) \int \frac {-2-3 i c x}{x^3 \left (1+c^2 x^2\right )} \, dx \\ & = -\frac {d (a+b \arctan (c x))}{3 x^3}-\frac {i c d (a+b \arctan (c x))}{2 x^2}-\frac {1}{6} (b c d) \int \left (-\frac {2}{x^3}-\frac {3 i c}{x^2}+\frac {2 c^2}{x}+\frac {c^3}{2 (-i+c x)}-\frac {5 c^3}{2 (i+c x)}\right ) \, dx \\ & = -\frac {b c d}{6 x^2}-\frac {i b c^2 d}{2 x}-\frac {d (a+b \arctan (c x))}{3 x^3}-\frac {i c d (a+b \arctan (c x))}{2 x^2}-\frac {1}{3} b c^3 d \log (x)-\frac {1}{12} b c^3 d \log (i-c x)+\frac {5}{12} b c^3 d \log (i+c x) \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.04 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.89 \[ \int \frac {(d+i c d x) (a+b \arctan (c x))}{x^4} \, dx=-\frac {d \left (2 a+3 i a c x+b c x+b (2+3 i c x) \arctan (c x)+3 i b c^2 x^2 \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1,\frac {1}{2},-c^2 x^2\right )+2 b c^3 x^3 \log (x)-b c^3 x^3 \log \left (1+c^2 x^2\right )\right )}{6 x^3} \]
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Time = 0.48 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.87
method | result | size |
parts | \(a d \left (-\frac {i c}{2 x^{2}}-\frac {1}{3 x^{3}}\right )+b d \,c^{3} \left (-\frac {\arctan \left (c x \right )}{3 c^{3} x^{3}}-\frac {i \arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i}{2 c x}-\frac {1}{6 c^{2} x^{2}}-\frac {\ln \left (c x \right )}{3}+\frac {\ln \left (c^{2} x^{2}+1\right )}{6}-\frac {i \arctan \left (c x \right )}{2}\right )\) | \(92\) |
derivativedivides | \(c^{3} \left (a d \left (-\frac {1}{3 c^{3} x^{3}}-\frac {i}{2 c^{2} x^{2}}\right )+b d \left (-\frac {\arctan \left (c x \right )}{3 c^{3} x^{3}}-\frac {i \arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i}{2 c x}-\frac {1}{6 c^{2} x^{2}}-\frac {\ln \left (c x \right )}{3}+\frac {\ln \left (c^{2} x^{2}+1\right )}{6}-\frac {i \arctan \left (c x \right )}{2}\right )\right )\) | \(98\) |
default | \(c^{3} \left (a d \left (-\frac {1}{3 c^{3} x^{3}}-\frac {i}{2 c^{2} x^{2}}\right )+b d \left (-\frac {\arctan \left (c x \right )}{3 c^{3} x^{3}}-\frac {i \arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i}{2 c x}-\frac {1}{6 c^{2} x^{2}}-\frac {\ln \left (c x \right )}{3}+\frac {\ln \left (c^{2} x^{2}+1\right )}{6}-\frac {i \arctan \left (c x \right )}{2}\right )\right )\) | \(98\) |
parallelrisch | \(-\frac {3 i x^{3} \arctan \left (c x \right ) b \,c^{3} d -3 i a \,c^{3} d \,x^{3}-b \,c^{3} d \ln \left (c^{2} x^{2}+1\right ) x^{3}+2 b \,c^{3} d \ln \left (x \right ) x^{3}-c^{3} x^{3} d b +3 i x^{2} b \,c^{2} d +3 i x \arctan \left (c x \right ) b c d +3 i a c d x +b c d x +2 b d \arctan \left (c x \right )+2 a d}{6 x^{3}}\) | \(121\) |
risch | \(-\frac {\left (3 b c d x -2 i b d \right ) \ln \left (i c x +1\right )}{12 x^{3}}+\frac {d \left (5 b \,c^{3} \ln \left (-c x -i\right ) x^{3}-b \,c^{3} \ln \left (c x -i\right ) x^{3}-4 b \,c^{3} \ln \left (-x \right ) x^{3}-6 i b \,c^{2} x^{2}-6 i x a c +3 b c x \ln \left (-i c x +1\right )-2 i b \ln \left (-i c x +1\right )-2 x b c -4 a \right )}{12 x^{3}}\) | \(129\) |
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Time = 0.25 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.03 \[ \int \frac {(d+i c d x) (a+b \arctan (c x))}{x^4} \, dx=-\frac {4 \, b c^{3} d x^{3} \log \left (x\right ) - 5 \, b c^{3} d x^{3} \log \left (\frac {c x + i}{c}\right ) + b c^{3} d x^{3} \log \left (\frac {c x - i}{c}\right ) + 6 i \, b c^{2} d x^{2} + 2 \, {\left (3 i \, a + b\right )} c d x + 4 \, a d - {\left (3 \, b c d x - 2 i \, b d\right )} \log \left (-\frac {c x + i}{c x - i}\right )}{12 \, x^{3}} \]
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Time = 2.60 (sec) , antiderivative size = 197, normalized size of antiderivative = 1.86 \[ \int \frac {(d+i c d x) (a+b \arctan (c x))}{x^4} \, dx=- \frac {b c^{3} d \log {\left (27 b^{2} c^{7} d^{2} x \right )}}{3} - \frac {b c^{3} d \log {\left (27 b^{2} c^{7} d^{2} x - 27 i b^{2} c^{6} d^{2} \right )}}{12} + \frac {5 b c^{3} d \log {\left (27 b^{2} c^{7} d^{2} x + 27 i b^{2} c^{6} d^{2} \right )}}{12} + \frac {\left (- 3 b c d x + 2 i b d\right ) \log {\left (i c x + 1 \right )}}{12 x^{3}} + \frac {\left (3 b c d x - 2 i b d\right ) \log {\left (- i c x + 1 \right )}}{12 x^{3}} + \frac {- 2 a d - 3 i b c^{2} d x^{2} + x \left (- 3 i a c d - b c d\right )}{6 x^{3}} \]
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Time = 0.29 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.82 \[ \int \frac {(d+i c d x) (a+b \arctan (c x))}{x^4} \, dx=-\frac {1}{2} i \, {\left ({\left (c \arctan \left (c x\right ) + \frac {1}{x}\right )} c + \frac {\arctan \left (c x\right )}{x^{2}}\right )} b c d + \frac {1}{6} \, {\left ({\left (c^{2} \log \left (c^{2} x^{2} + 1\right ) - c^{2} \log \left (x^{2}\right ) - \frac {1}{x^{2}}\right )} c - \frac {2 \, \arctan \left (c x\right )}{x^{3}}\right )} b d - \frac {i \, a c d}{2 \, x^{2}} - \frac {a d}{3 \, x^{3}} \]
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\[ \int \frac {(d+i c d x) (a+b \arctan (c x))}{x^4} \, dx=\int { \frac {{\left (i \, c d x + d\right )} {\left (b \arctan \left (c x\right ) + a\right )}}{x^{4}} \,d x } \]
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Time = 0.98 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.66 \[ \int \frac {(d+i c d x) (a+b \arctan (c x))}{x^4} \, dx=\frac {b\,c^3\,d\,\ln \left (c^2\,x^2+1\right )}{6}-\frac {\frac {a\,d}{3}-x^5\,\left (\frac {b\,c^5\,d}{6}+\frac {a\,c^5\,d\,1{}\mathrm {i}}{2}\right )+\frac {b\,d\,\mathrm {atan}\left (c\,x\right )}{3}+\frac {c\,d\,x\,\left (b+a\,3{}\mathrm {i}\right )}{6}+\frac {c^2\,d\,x^2\,\left (2\,a+b\,3{}\mathrm {i}\right )}{6}+\frac {b\,c^4\,d\,x^4\,1{}\mathrm {i}}{2}+\frac {b\,c^2\,d\,x^2\,\mathrm {atan}\left (c\,x\right )}{3}+\frac {b\,c^3\,d\,x^3\,\mathrm {atan}\left (c\,x\right )\,1{}\mathrm {i}}{2}+\frac {b\,c\,d\,x\,\mathrm {atan}\left (c\,x\right )\,1{}\mathrm {i}}{2}}{c^2\,x^5+x^3}-\frac {b\,c^3\,d\,\ln \left (x\right )}{3}-\frac {b\,d\,\mathrm {atan}\left (\frac {c^2\,x}{\sqrt {c^2}}\right )\,{\left (c^2\right )}^{3/2}\,1{}\mathrm {i}}{2} \]
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